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Jquery Ajax Error Status 200 Ok


Search for the comment "// If we have data, let's convert it" in jquery-1.9.1.js to see exactly where this is happening. I am able to delete content but I am not getting this message. It is worth noting that an empty response is also considered invalid JSON; you could return {} or null for example which validate as JSON. Should a router use SLAAC for IPv6 address assignment? have a peek at this web-site

By sending http status code of 200, I am expecting jQuery to treat this as a successful request. Send Cancel From : guestTo : Subject : Content : Type the characters you see in the picture below. Sign in using Search within: Articles Quick Answers Messages Use my saved content filters home articles Chapters and Sections> Search Latest Articles Latest Tips/Tricks Top Articles Beginner Articles Technical Blogs Posting/Update Do I need to reference the json library or is this included with jquery?

Ajax Request Return 200 Ok But Error Event Is Fired Instead Of Success

This means that if server returns invalid JSON with a 200 OK status then jQuery fires the error function and set the textStatus parameter to "parsererror". Drawing a k-ary tree using TikZ without overlap Conditional summation C++ delete a pointer (free memory) How exactly std::string_view is faster than const std::string&? If service method is not returning anything it means that return type is void. Each function will be called in turn.

jquery expects json, so it tries to parse the response text as json. I'm using the built-in ASP.NET Development server. So in your case dataType: 'json', is set and as you mentioned at the comment section you have set string at the backend, so you need to change your datatype to Ajax Status 200 Means That is what I ended up doing anyway.Thank you very much for your time.

Follow him on Twitter, or befriend him on Facebook or Google Plus. Ajax Error 200 Parsererror I am adding my code below: jQuery Code var row = "1"; var json = "{'TwitterId':'" + row + "'}"; $.ajax({ type: 'POST', url: 'Jqueryoperation.aspx?Operation=DeleteRow', contentType: 'application/json; charset=utf-8', data: json, dataType: Thanks for this, I was having the 200 OK and parsererror, the data I was returning was html, so I just set dataType: 'html' and BAM! See my edit answer. –Bharat Chodvadiya Apr 26 '13 at 8:34 Still just getting alert error –user2314110 Apr 26 '13 at 22:03 Note: if response is empty

If none is specified, jQuery will try to infer it based on the MIME type of the response (an XML MIME type will yield XML, in 1.4 JSON will yield a Jquery Ajax Check Status Code As in: $.ajax({ type: 'POST', url: 'Jqueryoperation.aspx?Operation=DeleteRow', contentType: 'application/json; charset=utf-8', data: json, dataType: 'text json', cache: false, success: AjaxSucceeded, error: AjaxFailed }); share|improve this answer answered Jun 15 '11 at 14:47 asked 3 years ago viewed 8575 times active 2 months ago Blog Stack Overflow Podcast #91 - Can You Stump Nick Craver? Application Lifecycle> Running a Business Sales / Marketing Collaboration / Beta Testing Work Issues Design and Architecture ASP.NET JavaScript C / C++ / MFC> ATL / WTL / STL Managed C++/CLI

Ajax Error 200 Parsererror

take the success and error methods out of the equation if you are positive that status code of 200 will always mean success and not an error page incorrectly returning a Apparently JS can't handle requests from one to the other. Ajax Request Return 200 Ok But Error Event Is Fired Instead Of Success Salman A Answer Email {} Share Your AJAX request contains the following setting: dataType: "json" The documentation states that jQuery: Evaluates the response as JSON and returns a JavaScript object. (...) {"readystate":4,"status":200,"statustext":"load"} I am adding my code here.

you can check whether a json is valid or not on jsonlint.com share|improve this answer edited Oct 27 '15 at 12:18 Mr_Green 18.8k2187153 answered May 31 '11 at 11:31 Salman A http://softacoustik.com/ajax-error/jquery-ajax-error-responsetext.php If anything else, it will alert ''An error occurred while processing the request."With firebug i have inspected the xhr object inside the error callback and it reports status of 200, thus Solution: make sure that the server returns valid JSON. I have { type: Schema.Types.Mixed}. Jquery Ajax Error Always Called

Reply terek-awan Member 80 Points 25 Posts Re: Simple Ajax returns 200 OK but fires error Oct 20, 2010 01:01 PM|terek-awan|LINK I tested this in Firefox 3.6and it worked there also. share|improve this answer answered Jan 30 '14 at 7:57 Paul 284 add a comment| up vote 1 down vote Use the following code to ensure the reponse is JSON format.. (PHP Treat my content as plain text, not as HTML Preview 0 … Existing Members Sign in to your account ...or Join us Download, Vote, Comment, Publish. http://softacoustik.com/ajax-error/jquery-and-ajax-and-error.php What to do with my out of control pre teen daughter Name spelling on publications Under what conditions is K-means clustering transformation-invariant?

Feeling stupid... Ajax Status Codes Maybe something is missing.What version of VisualStudioare you using. 2008 or 2010? But the error method is called.

I am adding my code below: jQuery Code var row = "1";
var json = "{'TwitterId':'" + row + "'}";
type: 'POST',
url: 'Jqueryoperation.aspx?Operation=DeleteRow',

I get the pop-up saying hello when button is clicked. Re: jQuery calls error callback on successful ajax request (status 200) 2 years ago I was getting status = parseerror and xhr.status = 200.The issue for me was the URL's inside Sometimes re-starting it helps with some issues. Ajax Error Readystate 4 Status 200 Linked 0 Ajax function success does not perform Related 749How can I get jQuery to perform a synchronous, rather than asynchronous, Ajax request?872How to manage a redirect request after a jQuery

Reply mdc1 Member 10 Points 73 Posts Re: Simple Ajax returns 200 OK but fires error Oct 21, 2010 04:41 AM|mdc1|LINK How bizzare! Thanks for any help. I am able to delete content but I am not getting this message. have a peek here Please suggest the correct way to solve this issue.